preg_replace first half of matches ?

[Porsche_maniak]

Hi !
I was wondering if it is possible to replace the first half of matches using only preg_replace ?

Like i have

[img=some1]
[img=some2]
[img=some3]
[img=some4]

$pattern='(\[img=(.*?)\])';
$test=preg_replace($pattern,'replaced',$test);
echo $test; 

The above code gives:

[img=replaced]
[img=replaced]
[img=replaced]
[img=replaced]

RESULT WANTED

[img=replaced]
[img=replaced]
[img=some3]
[img=some4]

PLS help !

Porsche_maniak Reviewed by Porsche_maniak on 16th Jan 2011. preg_replace first half of matches ? Hi ! I was wondering if it is possible to replace the first half of matches using only preg_replace ? Like i have Rating: 5

[litewarez]

People should read the manual a little more in depth:

mixed preg_replace ( mixed $pattern , mixed $replacement , mixed $subject [, int $limit = -1 [, int &$count ]] )

Meaning you can go:

$total_found = preg_match_all('(\[img=.*?\])',$subject);
$test = preg_replace($pattern,'replaced',$test, ceil($total_found / 2));
echo $test; 

The 4th param is the limit variable, not to be confused with the 5th param which is count